In Heald 2022 et al., on PED wound therapy, what was the total time to clinical healing in the dog case after initiation of treatment?
A. 10 days
B. 17 days
C. 47 days
D. 67 days
E. 90 days
Answer: 67 days
Explanation: Although wound size decreased over 10 days, full healing was confirmed on day 67.
In Heald 2022 et al., on PED wound therapy, which of the following statements best describes the cat's outcome after PED treatment?
A. PED treatment eliminated infection but wound did not close
B. PED had no effect on infection or wound size
C. PED reduced wound size, but bacteria persisted
D. PED resolved infection and wound healed by day 47
E. PED caused tissue necrosis and was discontinued
Answer: PED resolved infection and wound healed by day 47
Explanation: Culture on day 17 showed no infection, and the wound healed fully by day 47.
In Heald 2022 et al., on PED wound therapy, which bacterial species was isolated from the dog prior to treatment?
A. Staphylococcus aureus and Escherichia coli
B. Staphylococcus pseudintermedius and Streptococcus canis
C. Streptococcus pyogenes and Pseudomonas aeruginosa
D. Staphylococcus epidermidis and Pseudomonas aeruginosa
E. Methicillin-resistant Staphylococcus aureus (MRSA)
Answer: Staphylococcus pseudintermedius and Streptococcus canis
Explanation: Punch biopsy in the dog identified these two species before PED treatment.
In Heald 2022 et al., on PED wound therapy, what antimicrobial mechanism is attributed to the electroceutical dressing?
A. Generation of nitric oxide through enzymatic activity
B. Increased local heat via resistive current
C. Production of hydrogen sulfide by bacterial metabolism
D. Generation of hypochlorous acid at the anode site
E. Release of silver ions into the wound
Answer: Generation of hypochlorous acid at the anode site
Explanation: The PED generates HOCl via direct current, which contributes to bacterial inhibition.
In Heald 2022 et al., on PED wound therapy, what current level was applied to the dressing during treatment?
A. 6 mA
B. 3 mA
C. 1 mA
D. 0.6 mA
E. 0.1 mA
Answer: 0.6 mA
Explanation: The current was limited to 600 μA (0.6 mA) via a 10-kΩ resistor.